Monday, July 12, 2010

QUADRATIC EQUATIONS----WORD PROBLEMS?

if the perimeter of a rectangular plot is 68 m and length of its diagonal is 26 m fin it area



plz someone help.......

thnx
if perimeter is 68, then

2L 2W = 68

L W = 34

W = 34 - L

and since diagonal is 26,

L W = 26

L (34 - L) = 26

L 34 - 68L L = 26

2L - 68L 480 = 0

L - 34L 240 = 0

(L - 24)(L - 10) = 0

so L = 24, W = 10 area = 240 or L = 10, W = 24, area = 240

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