Calculate the mass of 2.50 mol of CH3OH(1)?

Just multiply the number of moles by its molar weight



molar weight of CH3OH:

C = 1 x 12.0 = 12.0

O= 1 x 16.0 = 16.0

H= 4 x 1.01 = 4.04



Total = 32.04 g/mole



(2.50 moles)(32.04 g/mole) = 80.1 g